Blinkova - Anisimova: betting tip (cf 1.90) and bets on the WTA Indian Wells match

Command Analysis

Blinkova has not been able to win a single tournament in five consecutive tournaments since the beginning of the year. It was at Indian Wells that the Russian tennis player broke her long series of setbacks in the first round. Anna sensationally defeated Dalma Galfi (6-4, 7-5). Thus, she improved on her last year's result on local courts when she was eliminated in the first round. It is important for Blinkova to score rating points, as due to recent failures, she currently occupies only 84th place in the rating.

Anisimova played in two tournaments after the quarterfinals of the Australian Open. In Doha, the American tennis player was eliminated in the second round when she could not finish the match against Pliskova. Next, in Dubai, Amanda scored a semi-final, losing to the future winner Pegula (6-1, 4-6, 3-6). In Indian Wells, the sixth racket of the world starts immediately from the second round and it is worth noting that in the last three starts here she has sheathed the racket at this stage.
Trends
The Totalbetis less than 2.5 sets
In all six matches since the beginning of the season, a minimum number of sets have been played with Blinkova's participation.
1.23Bet Effectiveness of sets: 2>1
According to this scenario, events developed in five consecutive matches with the participation of Anisimova.
2.21Tip and bets
Anisimova did not have any playing practice after the semifinal in Dubai, and it is far from certain that she will immediately be able to demonstrate a confident game and catch the right rhythm. Moreover, the tournament in Indian Wells cannot be called a success for her, at the last three starts here she invariably sheathed her racket at the end of the second round. Blinkova has interrupted her protracted series of defeats and may well keep a solid head start on a decent emotional rise, which is offered by bookmakers.
Our betting tip is that Blinkova will win with a handicap of (+7) games with a coefficient of 1.90
























