Sinner - Rublev: betting tip (cf 1.83) and bets on the ATP Rome match

Command Analysis

Sinner easily dealt with Andrea Pellegrino in the fourth round of the Masters in Rome. The 24-year-old Italian showed another high-quality game on the back line, beating his compatriot in two sets (6-2, 6-3). Earlier, Yannick had given Alexey Popyrin no chance in the third round, giving him only two games in the entire match, and at the start of the competition he broke the resistance of Sebastian Ofner.

Rublev scored a strong-willed victory over Nikoloz Basilashvili on the clay courts of Rome. The 28-year-old Russian lost in the first set, but managed to turn the tide of the meeting and put the squeeze on his opponent in three games (3-6, 7-6, 6-2). Before that, Andrey beat Alejandro Davidovich Fokina in two sets in the third round, and in the second round he was stronger than Miomir Kechmanovich.
Trends
The Totalbetis less than 18.5 games
Sinner has played less than 18.5 games in his last 5 matches.
1.87The 1st setbetis a total of less than 9.5 games
In Sinner's last 5 matches, fewer than 9.5 games were played in the first set.
1.50Bet Effectiveness of sets: 2>1
This was the scenario that unfolded in 4 of Sinner's last 5 matches.
2.31Tip and bets
Sinner is now in incredible playing form and literally does not notice the opponents on his way, continuing his flawless winning streak, which already counts 26 matches. The Italian has already defeated Alexei Popyrin and Andrea Pellegrino in Rome, demonstrating complete dominance in every component of the game.
Rublev, on the other hand, looks unstable: in the last round, he beat Nikoloz Basilashvili with great difficulty, losing the first set and making a lot of mistakes. The history of personal meetings in this pair is on the side of the favorite – Yannick leads 7-3 in the confrontation, including last year's defeat of Andrei on the clay courts of Paris. We expect that Sinner will upset Rublev again.
Our prediction is that Sinner will win with a handicap of (-6) games for a coefficient of 1.83






























